16x^2-16x-75=0

Solution for 16x^2-16x-75=0 equation:

16x^2-16x-75=0

a = 16; b = -16; c = -75;
Δ = b2-4ac
Δ = -162-4·16·(-75)
Δ = 5056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5056}=\sqrt{64*79}=\sqrt{64}*\sqrt{79}=8\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-8\sqrt{79}}{2*16}=\frac{16-8\sqrt{79}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+8\sqrt{79}}{2*16}=\frac{16+8\sqrt{79}}{32}
$